SOLUTION: i need an example of how to go about working out the solutions of an equation for e.g. Sinx= 0.5 with the domain XE[0,pi]
![d)/(dx)cos x^(0)= (A)-sin x^(0) (B)-(pi)/(180)sin x^(0) ( C) (pi)/(180)sin x^(0) (D) (2 pi)/(180)sin x^(0) d)/(dx)cos x^(0)= (A)-sin x^(0) (B)-(pi)/(180)sin x^(0) ( C) (pi)/(180)sin x^(0) (D) (2 pi)/(180)sin x^(0)](https://d10lpgp6xz60nq.cloudfront.net/web-thumb/415646124_web.png)
d)/(dx)cos x^(0)= (A)-sin x^(0) (B)-(pi)/(180)sin x^(0) ( C) (pi)/(180)sin x^(0) (D) (2 pi)/(180)sin x^(0)
![Find all solutions of the equation sin x - 1 = 0. Your answer is A + Bk \pi, where A = _____ with 0 less than A less than \pi, B = Find all solutions of the equation sin x - 1 = 0. Your answer is A + Bk \pi, where A = _____ with 0 less than A less than \pi, B =](https://homework.study.com/cimages/multimages/16/unitcircle5756593273254243558.png)
Find all solutions of the equation sin x - 1 = 0. Your answer is A + Bk \pi, where A = _____ with 0 less than A less than \pi, B =
![SOLVED: To be sloved by Matlab Question 3: Plot the following functions yl = sin(x*pi/180) ; y2 = cos(x*pi/180); y3 = tan(x*pi/180) ; in the interval x=[0:360] ; SOLVED: To be sloved by Matlab Question 3: Plot the following functions yl = sin(x*pi/180) ; y2 = cos(x*pi/180); y3 = tan(x*pi/180) ; in the interval x=[0:360] ;](https://cdn.numerade.com/ask_images/0b97efc8b3fa475183778140202402ac.jpg)
SOLVED: To be sloved by Matlab Question 3: Plot the following functions yl = sin(x*pi/180) ; y2 = cos(x*pi/180); y3 = tan(x*pi/180) ; in the interval x=[0:360] ;
![sin(180 + x) | sin(pi + x) | sin(180 + A) | sin(pi + A) | sin(180 + theta) | sin(pi + theta) - YouTube sin(180 + x) | sin(pi + x) | sin(180 + A) | sin(pi + A) | sin(180 + theta) | sin(pi + theta) - YouTube](https://i.ytimg.com/vi/0HfTL3n2MvQ/maxresdefault.jpg)