![Given that `sum_(n=1)^oo 1/n^2=pi^2/6 and sum_(n=1)^oo 1/(n^2+8n+16)=pi^2/a-b` where a in `N ... - YouTube Given that `sum_(n=1)^oo 1/n^2=pi^2/6 and sum_(n=1)^oo 1/(n^2+8n+16)=pi^2/a-b` where a in `N ... - YouTube](https://i.ytimg.com/vi/GA_KdA904fM/maxresdefault.jpg)
Given that `sum_(n=1)^oo 1/n^2=pi^2/6 and sum_(n=1)^oo 1/(n^2+8n+16)=pi^2/a-b` where a in `N ... - YouTube
Another Math - π^2/6 ≈ 1.644934066848226436472 The “Basel Problem” asks for the exact sum of the reciprocal square series: 1 + 1/2^2 + 1/3^2 + 1/4^2 + 1/5^2 + ... + 1/(n-1)^2 +
![Sara Venkatraman on Twitter: "What I think is especially striking is that the sum over just the odd integers (shown below) is (pi^2)/8, which is more than half of (pi^2)/6 ... https://t.co/0Ww3c3SxVK" / Sara Venkatraman on Twitter: "What I think is especially striking is that the sum over just the odd integers (shown below) is (pi^2)/8, which is more than half of (pi^2)/6 ... https://t.co/0Ww3c3SxVK" /](https://pbs.twimg.com/media/EwfV3jqW8AQhyCH.jpg)
Sara Venkatraman on Twitter: "What I think is especially striking is that the sum over just the odd integers (shown below) is (pi^2)/8, which is more than half of (pi^2)/6 ... https://t.co/0Ww3c3SxVK" /
![Ankur Handa on Twitter: "@InertialObservr If you plug t = 1/pi in the last two equations you arrive at the result. This one extends from the Basel problem also used to obtain Ankur Handa on Twitter: "@InertialObservr If you plug t = 1/pi in the last two equations you arrive at the result. This one extends from the Basel problem also used to obtain](https://pbs.twimg.com/media/EOmw31NVUAEL9w4.jpg:large)